tag:blogger.com,1999:blog-2962428197530077805.post105762693110399604..comments2024-03-18T22:57:59.502+00:00Comments on Clube de Matemática: Teorema de Pitágoras - Exame (1)Susana Martin Tenreirohttp://www.blogger.com/profile/09348824451614416496noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-2962428197530077805.post-46809496444128299132018-01-15T17:02:55.660+00:002018-01-15T17:02:55.660+00:00AE/AC = AD/AB AB= AC*AD/AE = 40*20/25 = 800 / 25...AE/AC = AD/AB AB= AC*AD/AE = 40*20/25 = 800 / 25 = 32<br />BCquadrado = ACquadrado-ABquadrado = 40quadrado - 32quadrado = 1600-1024 = 576 BC=576raizquadr = 24<br /><br />BC = 24DMITRIY 8A2noreply@blogger.comtag:blogger.com,1999:blog-2962428197530077805.post-15292559043581517022018-01-13T18:58:08.321+00:002018-01-13T18:58:08.321+00:00A resposta é: BC = 24.A resposta é: BC = 24.Rui Farianoreply@blogger.com